Comments on: .siblings() http://api.jquery.com/siblings/ jQuery API Reference Fri, 19 Aug 2011 09:06:00 +0000 hourly 1 http://wordpress.org/?v=3.3.1 By: Tenacious[B] http://api.jquery.com/siblings/comment-page-1/#comment-8457 Tenacious[B] Thu, 20 Jan 2011 01:56:15 +0000 http://api.jquery.com/?p=333#comment-8457 True, however .length in javascript starts at 1, not zero. True, however .length in javascript starts at 1, not zero.

]]> By: knoxy http://api.jquery.com/siblings/comment-page-1/#comment-8374 knoxy Sun, 16 Jan 2011 11:43:23 +0000 http://api.jquery.com/?p=333#comment-8374 counting starts at 0 in javascript counting starts at 0 in javascript

]]> By: TomB http://api.jquery.com/siblings/comment-page-1/#comment-8140 TomB Wed, 05 Jan 2011 21:11:20 +0000 http://api.jquery.com/?p=333#comment-8140 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.<br><br>1st list: siblings are for "one", "two" and four" ("three" is ignored as this is the selector)<br>2nd list: no siblings<br>3rd list: it loops through this one twice as there is a class selector of "hilite" applied to 2 list elements (1st loop makes up "eight","ten","eleven" ("nine" is ignored as this is the selector), 2nd loop makes up "eight", "nine", "ten" ("eleven" is ignored as this is the selector)) resulting in "eight", "nine" ten", "eleven"<br>Total =7 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.

1st list: siblings are for “one”, “two” and four” (“three” is ignored as this is the selector)
2nd list: no siblings
3rd list: it loops through this one twice as there is a class selector of “hilite” applied to 2 list elements (1st loop makes up “eight”,”ten”,”eleven” (“nine” is ignored as this is the selector), 2nd loop makes up “eight”, “nine”, “ten” (“eleven” is ignored as this is the selector)) resulting in “eight”, “nine” ten”, “eleven”
Total =7

]]> By: TomB http://api.jquery.com/siblings/comment-page-1/#comment-8141 TomB Wed, 05 Jan 2011 21:11:20 +0000 http://api.jquery.com/?p=333#comment-8141 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.<br><br>1st list: siblings are for "one", "two" and four" ("three" is ignored as this is the selector)<br>2nd list: no siblings<br>3rd list: it loops through this one twice as there is a class selector of "hilite" applied to 2 list elements (1st loop makes up "eight","ten","eleven" ("nine" is ignored as this is the selector), 2nd loop makes up "eight", "nine", "ten" ("eleven" is ignored as this is the selector)) resulting in "eight", "nine" ten", "eleven"<br>Total =7 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.

1st list: siblings are for “one”, “two” and four” (“three” is ignored as this is the selector)
2nd list: no siblings
3rd list: it loops through this one twice as there is a class selector of “hilite” applied to 2 list elements (1st loop makes up “eight”,”ten”,”eleven” (“nine” is ignored as this is the selector), 2nd loop makes up “eight”, “nine”, “ten” (“eleven” is ignored as this is the selector)) resulting in “eight”, “nine” ten”, “eleven”
Total =7

]]> By: TomB http://api.jquery.com/siblings/comment-page-1/#comment-8142 TomB Wed, 05 Jan 2011 21:11:20 +0000 http://api.jquery.com/?p=333#comment-8142 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.<br><br>1st list: siblings are for "one", "two" and four" ("three" is ignored as this is the selector)<br>2nd list: no siblings<br>3rd list: it loops through this one twice as there is a class selector of "hilite" applied to 2 list elements (1st loop makes up "eight","ten","eleven" ("nine" is ignored as this is the selector), 2nd loop makes up "eight", "nine", "ten" ("eleven" is ignored as this is the selector)) resulting in "eight", "nine" ten", "eleven"<br>Total =7 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.

1st list: siblings are for “one”, “two” and four” (“three” is ignored as this is the selector)
2nd list: no siblings
3rd list: it loops through this one twice as there is a class selector of “hilite” applied to 2 list elements (1st loop makes up “eight”,”ten”,”eleven” (“nine” is ignored as this is the selector), 2nd loop makes up “eight”, “nine”, “ten” (“eleven” is ignored as this is the selector)) resulting in “eight”, “nine” ten”, “eleven”
Total =7

]]> By: TomB http://api.jquery.com/siblings/comment-page-1/#comment-8143 TomB Wed, 05 Jan 2011 21:11:20 +0000 http://api.jquery.com/?p=333#comment-8143 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.<br><br>1st list: siblings are for "one", "two" and four" ("three" is ignored as this is the selector)<br>2nd list: no siblings<br>3rd list: it loops through this one twice as there is a class selector of "hilite" applied to 2 list elements (1st loop makes up "eight","ten","eleven" ("nine" is ignored as this is the selector), 2nd loop makes up "eight", "nine", "ten" ("eleven" is ignored as this is the selector)) resulting in "eight", "nine" ten", "eleven"<br>Total =7 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.

1st list: siblings are for “one”, “two” and four” (“three” is ignored as this is the selector)
2nd list: no siblings
3rd list: it loops through this one twice as there is a class selector of “hilite” applied to 2 list elements (1st loop makes up “eight”,”ten”,”eleven” (“nine” is ignored as this is the selector), 2nd loop makes up “eight”, “nine”, “ten” (“eleven” is ignored as this is the selector)) resulting in “eight”, “nine” ten”, “eleven”
Total =7

]]> By: TomB http://api.jquery.com/siblings/comment-page-1/#comment-8144 TomB Wed, 05 Jan 2011 21:11:20 +0000 http://api.jquery.com/?p=333#comment-8144 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.<br><br>1st list: siblings are for "one", "two" and four" ("three" is ignored as this is the selector)<br>2nd list: no siblings<br>3rd list: it loops through this one twice as there is a class selector of "hilite" applied to 2 list elements (1st loop makes up "eight","ten","eleven" ("nine" is ignored as this is the selector), 2nd loop makes up "eight", "nine", "ten" ("eleven" is ignored as this is the selector)) resulting in "eight", "nine" ten", "eleven"<br>Total =7 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.

1st list: siblings are for “one”, “two” and four” (“three” is ignored as this is the selector)
2nd list: no siblings
3rd list: it loops through this one twice as there is a class selector of “hilite” applied to 2 list elements (1st loop makes up “eight”,”ten”,”eleven” (“nine” is ignored as this is the selector), 2nd loop makes up “eight”, “nine”, “ten” (“eleven” is ignored as this is the selector)) resulting in “eight”, “nine” ten”, “eleven”
Total =7

]]> By: TomB http://api.jquery.com/siblings/comment-page-1/#comment-8145 TomB Wed, 05 Jan 2011 21:11:20 +0000 http://api.jquery.com/?p=333#comment-8145 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.<br><br>1st list: siblings are for "one", "two" and four" ("three" is ignored as this is the selector)<br>2nd list: no siblings<br>3rd list: it loops through this one twice as there is a class selector of "hilite" applied to 2 list elements (1st loop makes up "eight","ten","eleven" ("nine" is ignored as this is the selector), 2nd loop makes up "eight", "nine", "ten" ("eleven" is ignored as this is the selector)) resulting in "eight", "nine" ten", "eleven"<br>Total =7 The key to this is to remember that the selector loops through each list item where the criteria is met one-at-a-time.

1st list: siblings are for “one”, “two” and four” (“three” is ignored as this is the selector)
2nd list: no siblings
3rd list: it loops through this one twice as there is a class selector of “hilite” applied to 2 list elements (1st loop makes up “eight”,”ten”,”eleven” (“nine” is ignored as this is the selector), 2nd loop makes up “eight”, “nine”, “ten” (“eleven” is ignored as this is the selector)) resulting in “eight”, “nine” ten”, “eleven”
Total =7

]]> By: Zq010 http://api.jquery.com/siblings/comment-page-1/#comment-7941 Zq010 Wed, 29 Dec 2010 12:15:22 +0000 http://api.jquery.com/?p=333#comment-7941 var len = $(".hilite").siblings()<br> .css("color", "red")<br> .length;<br> $("b").text(len);<br>In the above example,I want to know why the 'len'=7,I think it is 8; var len = $(“.hilite”).siblings()
.css(“color”, “red”)
.length;
$(“b”).text(len);
In the above example,I want to know why the 'len'=7,I think it is 8;

]]> By: Zq010 http://api.jquery.com/siblings/comment-page-1/#comment-7822 Zq010 Wed, 29 Dec 2010 04:15:22 +0000 http://api.jquery.com/?p=333#comment-7822 var len = $(".hilite").siblings()<br> .css("color", "red")<br> .length;<br> $("b").text(len);<br>In the above example,I want to know why the 'len'=7,I think it is 8; var len = $(“.hilite”).siblings()
.css(“color”, “red”)
.length;
$(“b”).text(len);
In the above example,I want to know why the 'len'=7,I think it is 8;

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