Comments on: .prevAll() http://api.jquery.com/prevAll/ jQuery API Reference Fri, 19 Aug 2011 09:06:00 +0000 hourly 1 http://wordpress.org/?v=3.3.1 By: Heitor Salazar Baldelli http://api.jquery.com/prevAll/comment-page-1/#comment-8067 Heitor Salazar Baldelli Thu, 06 May 2010 01:23:22 +0000 http://api.jquery.com/?p=329#comment-8067 The jQuery object does not extend all native array functions, so you must revert explicity to have the inverse order.<br><br>Array.prototype.reverse.call($([selector]).prevAll()); <br><br>However the order returned is the expected order by the name of the method. As you should use the selected element as reference. The jQuery object does not extend all native array functions, so you must revert explicity to have the inverse order.

Array.prototype.reverse.call($([selector]).prevAll());

However the order returned is the expected order by the name of the method. As you should use the selected element as reference.

]]> By: Heitor http://api.jquery.com/prevAll/comment-page-1/#comment-3561 Heitor Wed, 05 May 2010 17:23:22 +0000 http://api.jquery.com/?p=329#comment-3561 The jQuery object does not extend all native array functions, so you must revert explicity to have the inverse order.<br>Array.prototype.reverse.call($([selector]).prevAll()); The jQuery object does not extend all native array functions, so you must revert explicity to have the inverse order.
Array.prototype.reverse.call($([selector]).prevAll());

]]> By: Andrew http://api.jquery.com/prevAll/comment-page-1/#comment-10822 Andrew Wed, 21 Apr 2010 07:59:00 +0000 http://api.jquery.com/?p=329#comment-10822 It would be really cool if this order was documented (and guaranteed), and e.g. $(this).prevAll('selector').eq(0) documented as the way to get "the last element previous to this which matches the selector", and likewise (but all swapped around) for next. Or is there some more elegant way to do that that I'm missing? It would be really cool if this order was documented (and guaranteed), and e.g. $(this).prevAll(‘selector’).eq(0) documented as the way to get “the last element previous to this which matches the selector”, and likewise (but all swapped around) for next. Or is there some more elegant way to do that that I’m missing?

]]> By: Hej http://api.jquery.com/prevAll/comment-page-1/#comment-1842 Hej Mon, 22 Mar 2010 22:24:06 +0000 http://api.jquery.com/?p=329#comment-1842 "Locate all the divs in front of the last div and give them a class" should be "Locate all the divs before/preceding the last div and give them a class" “Locate all the divs in front of the last div and give them a class” should be “Locate all the divs before/preceding the last div and give them a class”

]]> By: Elod Csirmaz http://api.jquery.com/prevAll/comment-page-1/#comment-912 Elod Csirmaz Wed, 10 Feb 2010 12:46:20 +0000 http://api.jquery.com/?p=329#comment-912 The order of prevAll elements: This is not documented here, but after some testing, it seems that they are in the reverse order. That is, $(this).prevAll().eq(0) is the element immediately preceding 'this'. The order of prevAll elements: This is not documented here, but after some testing, it seems that they are in the reverse order. That is, $(this).prevAll().eq(0) is the element immediately preceding 'this'.

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