Comments on: jQuery.inArray()

By: Amjad Masad

Amjad Masad — Sat, 15 Jan 2011 19:13:18 +0000

You could easily convert the returned value from inArray to boolean, !!~jQuery.inArray(elm, arr)

By: Karl Swedberg

Karl Swedberg — Sat, 27 Nov 2010 08:58:59 +0000

Already answered the question above ( http://api.jquery.com/jQuery.i... ) as did John Resig in reply to Znarkus on the forum.

By: Karl Swedberg

Karl Swedberg — Sat, 27 Nov 2010 00:58:59 +0000

Already answered the question above ( http://api.jquery.com/jQuery.inArray/#comment-31436032 ) as did John Resig in reply to Znarkus on the forum.

By: Fabrizio Parrella

Fabrizio Parrella — Thu, 25 Nov 2010 17:23:00 +0000

I meant to post this under Karl Swedberg message

By: Fabrizio

Fabrizio — Thu, 25 Nov 2010 14:22:11 +0000

shouldn't:
- return array.indexOf( elem );
be changed with something similar to
var ret = array.indexOf( elem );
return (ret==undefined)?-1:ret;

By: Znarkus

Znarkus — Tue, 16 Nov 2010 04:06:38 +0000

I asked the same thing a while back in the jQuery forum http://forum.jquery.com/topic/inarray

By: Billy Wenge-Murphy

Billy Wenge-Murphy — Tue, 16 Nov 2010 00:19:31 +0000

>Array.indexOf() is not supported in every browser
Then why not call it indexOf and make it available when the native alternative isn't?

I expect an “inArray” function to act like PHP in_array

By: Znarkus

Znarkus — Tue, 09 Nov 2010 17:08:09 +0000

Should the docs say that it checks type?

By: BertrandChorizo

BertrandChorizo — Sat, 02 Oct 2010 07:03:55 +0000

it does

By: jesso

jesso — Fri, 17 Sep 2010 20:46:00 +0000

It may be obvious to some, but there is a difference between numbers and strings! parseInt() can solve the problem.
Ex:
var number = 32;
var arr = [14, 28, 44, "32"];
if(jQuery.inArray(number,arr) > -1) {
alert(‘found’);
}
// false because “32″ is a string in the array