Comments on: .hasClass()

By: Dasiepi

Dasiepi — Sat, 29 Jan 2011 21:47:29 +0000

if i add a class dinamically (say “active” ) with addClass and then check with hasClass it returns false.

By: Bronza

Bronza — Thu, 13 Jan 2011 18:54:50 +0000

what's the method to get the className of an element!?

By: LucMorizur

LucMorizur — Thu, 09 Dec 2010 05:12:05 +0000

Hi ;

I think that what Karl was saying, is that if you need to test if element has classes 'foo' or 'bar' or both these classes, you should write:
if ($(this).is('.foo, .bar'))

By: LucMorizur

LucMorizur — Wed, 08 Dec 2010 21:12:05 +0000

Hi ;

I think that what Karl was saying, is that if you need to test if element has classes 'foo' or 'bar' or both these classes, you should write:
if ($(this).is('.foo, .bar'))

By: Karl Swedberg

Karl Swedberg — Tue, 23 Nov 2010 16:35:37 +0000

separate the classes with a comma:
$(this).is('.foo, .bar')

By: Brian Dichiara

Brian Dichiara — Fri, 19 Nov 2010 15:06:26 +0000

What about if I wanted to check if it had ANY of the classes? .this OR .that Something built in for this?

By: Pradeepa Kundapur

Pradeepa Kundapur — Mon, 08 Nov 2010 09:49:56 +0000

yeah Mikro ur r8

By: Mirko

Mirko — Tue, 03 Aug 2010 18:21:03 +0000

if(!$('tr').hasClass(“termid-24″)){
}

By: Mitchell

Mitchell — Thu, 29 Jul 2010 03:18:08 +0000

That will only match the first in a list of space-separated classes. It will give a false negative for INPUT CLASS=”foo req-if-checked-bar”

By: Karl Swedberg

Karl Swedberg — Thu, 25 Mar 2010 02:42:00 +0000

Rather than use .hasClass() for that, I'd recommend using .is(). $(this).is('.foo.bar') would give the same result as $(this).is('.bar.foo')